Now, you would think this is where things become much more complicated because there is another option to use to bet (a 2-team parlay with a side bet on a single team), but in actuality it is just as simple as our prior example. Why? Because it is NEVER advantageous to the gambler to do a 2-game parlay and one side team bet on 3 teams that they are equally confident on. Just use this as a rule to live by in gambling, because mathematically speaking there is no reason to bet on a 2-team parlay and a one game side bet (assuming equal dispersion of funds and equal confidence).
So this only leaves two options, parlaying the 3 teams or betting on each separately. So when does one become advantageous over the other? Well reference my first article that drives a little deeper into this issue. For a little summary of everything:
Straight bet:
Win all 3: $91
Win 2, Lose 1: $27
Win 1, Lose 2: -$36
Lose all 3: -$100
Parlay:
Win: $600
Lose -$100
Times each can occur on a single bet:
Win all 3= 1
Win 2, Lose 1= 3
Win 1, Lose 2= 3
Lose all 3= 1
Times each can occur on a parlay:
Win= 1
Lose= 7
After all of the calcuations it was concluded that both bets would earn you the same amount at 52.23% where you are losing about $0.25 per bet.
It is interesting to note that 3-game parlays actually pay off better even before the break even point of both bets.
So in conclusion:
If you're winning percentage is below 52.23% then bet on each team individually
If you're winning percentage is above 52.23% then parlay the bet
Never do a 2-team parlay with a side bet of one team (you are better off either parlaying them all or betting on each separately)
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